Math, asked by quaviabdu, 4 months ago

Diagram of the adjacent picture frame has outer dimensions
28 cm x 24 cm and inner dimensions 20 cm x 16 cm. Find
the area of shaded part of frame, if width of each section is
the same.
16cm
20cm
28cm​

Answers

Answered by Anonymous
13

Answer:

Step-by-step explanation:

Mensuration:

Mensuration is the branch of mathematics which concerns itself with the measurement of Lengths, areas & volume of different geometrical shapes or figures.

Plane Figure: A figure which lies in a plane is called a plane figure.

For e.g:  a rectangle, square, a rhombus, a parallelogram, a trapezium.

Perimeter:

The perimeter of a closed plane figure is the total length of its boundary.

In case of a triangle or a polygon the perimeter is  the sum of the length of its sides.

Unit of perimeter is a centimetre  (cm), metre(m) kilometre(km) e.t.c

Area: The area of the plane figure is the measure of the surface enclose by its boundary.

The area of a triangle are a polygon is the measure of the surface enclosed by its sides.

A square centimetre (cm²) is generally taken at the standard unit of an area. We use square metre (m²) also for the units of area.

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Solution:

In Figure (I) and (II) are similar in dimensions & also figures (III) and (IV) are similar in dimensions.

Width is 28 - 24 = 4 cm

Width is same of each section.

Width is height of all the trapezium.

Area of figure (I) = Area of trapezium

= ½(sum of parallel sides) ( height)

= ½ (28+20)(4)

= ½( 48)(4)

= 48×2

= 96 cm²

Area of figure (II) = 96 cm²

Area of figure (I) = Area of figure (II) = 96 cm²

 

Area of figure (III)

= Area of trapezium =  ½(sum of parallel sides) ( height)

= ½(24+16)(4)

= ½(40)(4)

= 40× 2

= 80 cm²

Area of figure (IV) = 80 cm²

Area of figure (III) = Area of figure (IV) = 80 cm²

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Hope this will help you...

Answered by Anonymous
4

Answer:

Above answer is correct

Mark above answer as brainliest

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