Question

diagram of when the object is placed at infinity by concave lens​

Answer 1

Here is the required diagram

$\setlength{\unitlength}{25} \begin{picture}(10,10)\thicklines\qbezier(7,6)(8,3)(7,1) \put(1,3.5){\line(1,0){6.5}} \put(1,3.5){\line(1,0){6.5}}\put(4.5,3.5){\vector(0,1){1}}\put(4.5,4.5){\vector(1,0){1}}\put(4.5,4.5){\line(1,0){2.9}}\put(4.5,4.5){\line(1, - 1){2.8}}\put(7.4,4.5){\line( - 2, - 1){6.5}}\put(4.5,4.5){\vector(1, - 1){0.7}}\put(4.5,4.5){\vector(1, - 1){2}}\put(7.4,4.5){\vector( - 2, - 1){1}}\put(7.4,4.5){\vector( - 2, - 1){4}}\put(7.3,1.7){\line( - 1,0){5.5}}\put(1.8,3.5){\vector(0, - 1){1.8}}\put(7.3,1.7){\vector( - 1,0){3}}\put(4.4,3.1){ \tt B }\put(3,3.1){ \tt C }\put(1.75,3.75){ \tt B' }\put(1.75,1.2){ \tt A' }\put(5.25,3.1){ \tt F }\put(4.4,4.75){ \tt A }\put(7.5,4.7){ \tt L }\put(7.7,3.25){ \tt P }\put(7.4,1.5){ \tt N }\put(3.125,3.5){\circle*{0.15}}\put(5.4,3.5){\circle*{0.15}}\put(7.1,5.7){\line(1, - 1){0.5}}\put(7.3,4.8){\line(1, - 1){0.5}}\put(7.4,4.1){\line(1, - 1){0.5}}\put(7.1,1.3){\line(1, - 1){0.5}}\put(7.4,2.4){\line(1, - 1){0.5}}\put(7.5,3){\line(1, - 1){0.5}}\end{picture}$

Note

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