Question

Diamagnetic species are those which contain no unpaired electrons. Which among the following are diamagnetic?(a) N2                     (b) N22-  (c) 02                      (d) O22-​

Answer 1

Answer:

a,d

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Answer 2

Answer:Solution :

(a,d)

a) Electronic configuration of N2=σ1s2,σ⋆1s2,σ2s2,π2p2x=π2p2y,σ2p2z.

It has unpaired electron indicates diamagnetic species.

b) Electronic configuration of N2−2 ion =σ1s2,σ⋆s2,σ2s2,σ⋆2s2,π2p2x=π22y,σ2p2z,π⋆p1x=π⋆2p2y

It has two unpaired electrons, paramagnetic in nature.

c) Electronic configuration of O2 = σ1s2,σ⋆2s2,π2p2s,σ⋆2s2,σ2p2z,π2p2x=π2p2y,π⋆2p1x=π⋆2p2y

The presence of two unpaired electrons shows its paramagnetic nature.

d) Electronic configuration of O2−2=σ1s2,σ⋆1s2,σ2s2,σ2p2z,π2p2x=π2p2y,π⋆2p2x=π⋆2p2y

It contains no unpaired electron, therefore it is diamagnetic in nature.

Explanation: