Diamete of a circular park is 84m a 3.5m broad road runs around it find cost of construction of road at 200perm square
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D = 84 m r = 84/2. r = 42 m
breadth = 3.5 m
CSA = 2πrsquare
= 2×22/7×1764
= 2×38808/7
= 77616/7
= 11088-3.5
= 11084.5 sq.m.
= cost of construction of road = 11084.5×200 = 22,16,900 Rs
breadth = 3.5 m
CSA = 2πrsquare
= 2×22/7×1764
= 2×38808/7
= 77616/7
= 11088-3.5
= 11084.5 sq.m.
= cost of construction of road = 11084.5×200 = 22,16,900 Rs
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