diameter = 20 m height= 21 m class 8
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Answer:
Given length of cylindrical part as 2.5m
Hence , the height of the cone part =7.5m
r=20m for both Cylinder and cone
The area of canvas required=Surface area of Cylindrical and cone parts of tent
A=2πrh+πr(
h
2
+r
2 )
A=2π×20×2.5+π×20(202 +7.52)
A=1656.25m
2
Cost of canvasing =165625rupees
Step-by-step explanation:
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