Diameter and length of a roller are 84cm and 120 respectively in how many revolution can the roller level the playground of area 1584m squ
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Answered by
37
Radius= 42 cm= 0.42 m
Height= 120 cm= 1.2 m
CSA of roller= 2×22/7×0.42×1.2= 31.68 sq. m
No. of revolution= 1584/31.68 = 50
Height= 120 cm= 1.2 m
CSA of roller= 2×22/7×0.42×1.2= 31.68 sq. m
No. of revolution= 1584/31.68 = 50
Answered by
59
diameter - 84 cm
radius - 84÷2 = 24 cm
height - 120 cm
area - 1584m sq. = 1584×100×100 =15840000cm sq.
(two times 100 becz there is m.sq.so)
Area of 1 revolution CSA- 2πrh
= 2×22/7×42×120
(pleast cut 42 from 7 by 6 times ) i.e,2×22×6×120 = 31680
No. of revoltuions = total area covered ÷ Area of 1 revolution
= 15840000 ÷ 31680 = 500 revolutions, Ans.
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radius - 84÷2 = 24 cm
height - 120 cm
area - 1584m sq. = 1584×100×100 =15840000cm sq.
(two times 100 becz there is m.sq.so)
Area of 1 revolution CSA- 2πrh
= 2×22/7×42×120
(pleast cut 42 from 7 by 6 times ) i.e,2×22×6×120 = 31680
No. of revoltuions = total area covered ÷ Area of 1 revolution
= 15840000 ÷ 31680 = 500 revolutions, Ans.
mark me brainliest thanku..## u can also see in above pic ## mark brainliest
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