Question

Diameter and length of a roller is 84 cm and 12 cm respectively . In how many revolution can roller level up the ground of area 1584 m^2..

Answer 1

Answer:

Area covered in 1 revolution = CSA of the Roller

Length of the roller = 84 cm

Diameter of the roller = 12 cm

Radius of the roller = 6 cm.

CSA of Roller = 2πrh

→ CSA = 2 × 22/7 × 6 × 84

→ CSA = 3168 cm² = 0.3168 m²

Therefore in 1 revolution, the roller covers 0.3168 cm².

→ 1584 m² = n × 0.3168

where, n is the number of revolutions.

→ n = 1584 / 0.3168

→ n = 5000

Therefore after 5000 revolutions, the roller can cover an area of 1584m².

Answer 2

Answer:

Number of revolutions =5,000.

Step-by-step explanation:

➡ Given here .

♠ Length of roller = 84cm.

♠Diameter of roller =12cm.

So,

♠ Radius of the roller = 12/2 = 6cm.

➡Find Here,

♠Revolutions of roller .

Now,

➡Formula Used :-

♠Curved surface area of roller=2πrh

↪CSA =2×22/7 × 6×84.

↪CSA= 264×12

↪CSA= 3168 cm².

↪CSA= 0.3168 m².

➡As we know,

↪Area covered in 1Revolutions of roller = CSA of Roller .

So,

In 1 revolutions , roller covered 0.3168 m² area .

So,

♠Number of revolutions(n) = Total area /covered area by 1 revolutions .

↪n = 1584/0.3468

↪n= 1584×10000/3468.

↪n= 5,000.

➡Therefore,

♠ roller will 5,000 revolutions for covered 1584 m² area.