diameter of 0.84 long rollr is1.5 m. if it takes100 revolution.find cost of leveling ground at rate if 50 paise pet sq m
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diameter of the roller = 1.5 m
radius of roller = 1.5/2 m
height = 0.84 m
No. of revolutions = 100
curved surface area = 2×22/7×r×h
= 22*1.5*0.12
=3.96m*m
No. of revolutions = 100
cost of levelling = 0.5 $ * 3.96
= 1.98 m*m
radius of roller = 1.5/2 m
height = 0.84 m
No. of revolutions = 100
curved surface area = 2×22/7×r×h
= 22*1.5*0.12
=3.96m*m
No. of revolutions = 100
cost of levelling = 0.5 $ * 3.96
= 1.98 m*m
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