Question

Diameter of a capillary tube is 0.4*10^-3m, it is held vertically in liquid whose density is 0.8*10^3 kg/m and t is 9.8*10^-2n/m. determine the height to which the liquid will rise in tube

Answer 1

The height to which will rise is h= 12.5 cm

Explanation:

Height  of liquid column in a capillary is given by  h =  2Tcosθ  / ρgr

Where T =  surface  tension

ρ =  density of  liquid  

g = acceleration due to gravity

r = radius of capillary

θ = angle of contact

Radius of capillary r = D / 2 = 0.4×10−3 / 2  

                                = 0.2×10^−3 m

h = 2×9.8×10^−2×cos0° / 0.8×10^3×9.8×0.2×10^−3

h= 2×10^−2 / 0.8×0.2

h = 12.5×10^−2 m

h= 12.5 cm

Thus the height to which will rise is h= 12.5 cm

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Answer 2

Explanation:

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