diameter of a circle 21cm.what is the length of each side of an equitorial triangle whose perimeter is equal to the circumference of the circle
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Answered by
1
Answer:
In ∆ ABC A=B=C=60° and a=b=c= 21cm.
Radius of circumcircle (R) = a/2sinA =b/2sinB = c/2sinC
R =21/(2.sin60°)= 21/(2.√3/2) = 21/√3 cm
Area of the circumcircle =π.R^2 = (22×21×21)/(7×3) . cm^2
= 462 cm^2. Answer
Answered by
0
Answer:
462 cm^2.
Step-by-step explanation:
In ∆ ABC A=B=C=60° and a=b=c= 21cm.
Radius of circumcircle (R) = a/2sinA =b/2sinB = c/2sinC
R =21/(2.sin60°)= 21/(2.√3/2) = 21/√3 cm
Area of the circumcircle =π.R^2 = (22×21×21)/(7×3) . cm^2
= 462 cm^2. Answer.
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