diameter of a circle is 26cm and leangth of a chord of a circle is 24cm find the distance of the chord from centre
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Step-by-step explanation:
radius = 1/2 x diameter
= 1/2 x 26
= 13 cm
length of the chord = 24 cm
we know that perpendicular drawn from the centre of the circle to the chord bisects the chord.
half of length of the chord ( QP ) = 12 cm
radius of the circle ( OQ ) = 13cm
by applying Pythagoras theorem.
OQ2 = OP2 + PQ2
i.e
OQ2 - PQ2 = OP2 ( Distance of chord from center)
13² - 12square = op2
169 - 144 = op2
25 = op2
ie. op = 5 ( after taking square root)
the distance of chord is 5cm from the centre.
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