Question

diameter of a circle is 30cm and length of the chord of the circle is 24cm find the distance of the chord the centre​

Answer 1

$\sf{In \: the \: figure, \: length \: of \: chord \: AB=24cm.}$

$\sf{Now, \: we \: know \: that, \: in \: a \: circle, \: perpendicular \: from \: the \: centre \: bisects \: the \: chord.}$

$\sf{⇒AP=BP=12cm}$

$\sf{Radius AO=15cm}$

$\sf{Using \: pythagoras \: theorem, \: OP= \sqrt{(AO {}^{2} −AP {}^{2} )} =9cm}$

$\sf{ \purple{Hence \: the \: answer \: is \: 9cm}}$

Hope this helps you mate✌

Answer 2

Answer:

The answer according to Pythagoras theorem will be 9cm