Question

diameter of a circle s 26 cm and length of a chord of circle is 24 cm . find the distance of chord from the center

Answer 1

Answer:

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Step-by-step explanation:

d=26c.m.

r=13c.m

. if we draw a hieght to the cord from the center than the cord divided into two parts which are equal

let AB is the chord

and the height touches the chord at point X

than AX = BX

AX=24/2=12cm

OA is the radius which is equal to 13cm

in triangle OAX,measure of OXA =90degree

and OA is the hypotenus(h)

AX and OX are touching the right angle v so the are p and b

as to Pythagorean theorem,h^2=p^2+ b^2

OA^2=Ax^2+OX^2

13^2=12^2+OX^2

169= 144+ OX ^2

169-144=OX ^2

25=0X^2

OX =$\sqrt{25}$

ox=5

distance =5