Question

Diameter of eyeball of normal eye is 2.5 cm power of eye lens varies from

Answer 1

pls elaborate your question.

Answer 2

44 D to 40 D

Explanation:

An eye see distant objects with full relaxation.

So, [1 / (2.5 × 10⁻²)] – [1 / -∞] = 1 / f or, P = 1 / f = 1 / 2.5 × 10⁻² = 40 D

An eye see an object at 25 cm with strain [1 / (2.5 × 10⁻²)] – [1 / 2.5 × 10⁻²] = 1 / f

.·. P = 1 / f = 40 + 4 = 44 D