diameter of the base of a cone is 10.5cm and its slant height as 10cm . find its csa
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Answered by
12
r= 10.5/2
r = 5.25 cm
slant height (l) = 10 cm
so its curved surface area = πrl
now ,
= 22/7 × 5.25 × 10
= 22/7 × 525/100 × 10
= 22× 75/100 ×10
= 165 m^2 is the answer
r = 5.25 cm
slant height (l) = 10 cm
so its curved surface area = πrl
now ,
= 22/7 × 5.25 × 10
= 22/7 × 525/100 × 10
= 22× 75/100 ×10
= 165 m^2 is the answer
Answered by
2
Right circular cone:
If a right angled triangle is revolved about
one of the two sides forming a right angle keeping the other side fixed in
position then the solid so obtained by segments is called right circular cone.
Slant height:
The
length of the line segment joining the vertex to any point on a circular edge
of the base is called the slant height of the cone.
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Given: Diameter= 10.5 cm
Radius (r) = 10.5/2 cm = 5.25 cm
Slant height (l) = 10 cm
Curved surface area of the cone = (πrl)
=(22/7 × 5.25 × 10)
=165 cm²
Hence, the curved surface area of a cone =165cm²
=========================================================
Hope this will help you ..
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