Question

diameter of the circular Garden is 42 M there is a 3.5 M wide road around the garden find the area of the road​

Answer 1

road's inner radius = 21 M

road's outer radius = 24.5 M

inner area = 3.14·21·21

= 1384.74 M^2

outer area = 3.14·24.5·24.5

= 1884.785 M^2

road's area = 1884.785 - 1384.74

= 500.045 M^2

Answer 2

Diameter of circular garden = d = 42m

r1 = 21m

Width of road around garden = 3.5m

Thus,

Raduus of inner circle = r1 - 3.5m = 42-3.5 = 38.5=r2

Area of road = Area of circular garden - Area of inner circle

$area = \pi {r1}^{2} - \pi {r2}^{2}$

Area =

$\frac{22}{7} \times {42}^{2} - \frac{22}{7} \times {38.5}^{2}$

Area = 5544 - 4658.5

Area = 885.5sq.cm

Thus

Area of road = 885.5 sq.cm