Question

Diameter of the circular garden is 42m. There is a 3.5m wide road around the garden. Find the area of the road.
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Answer 1

Answer:

let

the smaller radius of circular garden is (r1)

r=42/2

r=21m

and the larger radius of garden is (r2)

R=r+3.5

R=21+3.5

R=24.5

ATQ

area of the road =

$\pi {r2}^{2} - \pi {r1}^{2} \\ = \pi( {24.5}^{2} - {21}^{2} ) \\ = \pi(600.25 - 441) \\ = \pi(159.25) \\ = \frac{22}{7} \times 159.25 \\ = 22 \times 22.75 \\ = 500.5 {m}^{2}$

hope it answer is correct

if it wrong so soo sorry bro