Question

Diameter of the metal ball measured by Vernier Calliper is 2.34. If least count of Vernier Calliper is 0.01 cm , calculate percentage error

Answer 1

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PERCENTAGE ERROR = FRACTIONAL ERROR × 100


FRACTIONAL ERROR = ABSOLUTE VALUE ÷ MEASURED VALUE


FRACTIONAL ERROR = 0.01 ÷ 2.34 = 0.00427

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NOW
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PERCENTAGE UNCERTANITY = FRACTIONAL ERROR × 100


PERCENTAGE UNCERTANITY = 0.00427 ×100


PERCENTAGE UNCERTANITY = 0.427 %


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Answer 2

Answer:

The percentage error is 0.427.

Explanation:

First, let's see the given formula;

$\mathrm{\frac{\Delta D}{D}=\frac{L.C.}{D_a} }$            (1)

Where,

$\mathrm{\frac{\Delta D}{D} }$=percentage error

L.C.=least count of the vernier Calliper

$\mathrm{D_a}$=actual diameter

From the question we have;

The actual diameter of the ball=2.34

The least count of the vernier calliper=0.01

By inserting the value of "$\mathrm{D_a}$" and "L.C." in equation (1) we get;

$\mathrm{\frac{\Delta D}{D}=\frac{0.01}{2.34} }$

$\mathrm{\frac{\Delta D}{D}=0.0042\times 100 }$

$\mathrm{\frac{\Delta D}{D}=0.427 }$          (2)

So, the percentage error is 0.427.

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