diametre CD of a circle with centre O is perpendicular to chord AB. if AB =12 cm and CE =3cm. find the radius of the circle
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by Pythagoras theorem
radius2= ab2+ ce2
=r2= 144+9
r2 =153
.
by Pythagoras theorem
radius2= ab2+ ce2
=r2= 144+9
r2 =153
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