Question

Dice have been designed so that in each case
the sum of opposite faces are equal. Three
such dice A, B, C are rolled and the sum of
the top faces is determined. One of the dice
is then turned upside down. The number
appearing at the top is added to the sum
obtained. The same die is again rolled and
the number appearing on the top face is
added to the sum obtained so far. What is the
final sum, if the faces showing up now are
respectively 3. 4.32
(1) 16
2) 18
19
(9) 20​

Answer 1

Answer:

i think the answer is 16