Question

dice is thrown once. Find the probability of getting.

(a)A prime number (b) a number lying between 2 and 6.​

Answer 1

$\Huge\mathcal\blue{\star{\underline{\underline{Answer}}}}$

$\large\orange{Probability (E) = \frac{Possible\; outcomes}{Total\; Outcomes}}$

$(a)\: Probability (Prime\: Number) = \Large\frac{3}{6} = \Large\frac{1}{3}$

$(b)\: Probability (E) = \Large\frac{3}{6} = \Large\frac{1}{2}$

Hope it helps úh

Answer 2

❥ $\huge\bold\green{\underline{Answer:}}$

$\Large\mathcal{\blue{Probability= \frac{Possible\: outcomes}{ Total\: outcomes}}}$

$(a)\: P(E) = \Large{\frac{3}{6} = \frac{1}{2}}$

$(b)\: P(E) = \Large{\frac{3}{6} = \frac{1}{2}}$

Hope it helps úh