dichlorination of pentane gives x structural isomers. the value of 5x/2 is
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To have a single mono-chloride , there should be only one type of H−atom. This is because, replacement of any H−atom leads to the formation of same product.
∴ The isomer C
5
H
12
that leads to a single mono-chloride is neo-pentane.
CH
3
−
CH
3
∣
C
∣
CH
3
−CH
3
ii) To have 3 isomeric mono-chlorides, the isomer should contain 3 different types of H−atoms.
∴ The isomer should be n−pentane.
CH
3
c
−
CH
2
b
−
CH
2
a
−
CH
2
b
−
CH
3
c
iii) To have 4 isomeric mono-chlorides, the isomer should contain 4 different types of H−atoms.
∴ The isomer is 2−methylbutane.
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