did anyone can solve this problem fast
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sum of angles in triangle = 180
angle A + angle B + angle C = 180
x + 3x + y = 180
4x + y = 180 ------ ( 1 )
also given ,
3y - 5x = 30 ------- ( 2 )
multiplying eq 1 by 3 we get
12x + 3y = 540 ------ ( 3 )
subtracting eq 2 from 3 we get
17 x = 510
x = 30
so one angle is 30°
another angle is 4x = 3 × 30 = 90°
remaining must be 60 °
so triangle is right angeled
angle A + angle B + angle C = 180
x + 3x + y = 180
4x + y = 180 ------ ( 1 )
also given ,
3y - 5x = 30 ------- ( 2 )
multiplying eq 1 by 3 we get
12x + 3y = 540 ------ ( 3 )
subtracting eq 2 from 3 we get
17 x = 510
x = 30
so one angle is 30°
another angle is 4x = 3 × 30 = 90°
remaining must be 60 °
so triangle is right angeled
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