Question

did I solve the sum correctly?​

Answer 1

Answer:

you did wrong

please follow my answer

let's consider side of first square is x and second square is y

than

(x)^2+(y)^2=400 equ 1

4x-4y=16 => x-y=4 equ 2

both side square of equ 2

(x-y)^2=(4)^2

((x)^2+(y)^2)-2(x)(y)=16

using equ 1

400-2xy=16

2xy=400-16=384

xy=192