diduce newtom 1st law of motion from 2ed law of motion
Nikhilsinghbisht:
write correct spelling
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Answered by
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If it is derive then the answer is
F=m×a
F=m×(v-u/t)
F=mv-mu/t
Ft=mv-mu
F=m×a
F=m×(v-u/t)
F=mv-mu/t
Ft=mv-mu
Answered by
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p=MV _(1)
where v=displacement/time
where displacement=acceleration
because a=v-u/t
where u is initial velocity i.e it is 0displaceme
therefore a=v-0/t
a=displacement-0/time/time
therefore a=displacement
keep the value of a in (1)
p=m(displacement/time)
p=m(acceleration/time)
p=m(v-u/time/time)
p=m(v-u)
where v=displacement/time
where displacement=acceleration
because a=v-u/t
where u is initial velocity i.e it is 0displaceme
therefore a=v-0/t
a=displacement-0/time/time
therefore a=displacement
keep the value of a in (1)
p=m(displacement/time)
p=m(acceleration/time)
p=m(v-u/time/time)
p=m(v-u)
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