didvide 20 ino 2 parts so that 5 times the larger number is equal to four more than seven times the smaller number
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Let x be larger number and y be smaller number:
A.T.Q:
x + y = 20 => x = 20 - y ..(1)
5x = 7y +4 ..(2)
Putting (1) in (2):
5(20-y) = 7y + 4
100 - 5y = 7y + 4
Now, transposing variable terms to one side and constant terms to the other:
-5y - 7y = 4 - 100
-12y = -96
y = -96/-12
y = 8 ...(3)
Putting (3) in (1):
x = 20 - 8
x = 12
Therefore, the larger number is 12 and smaller number is 8.
Hope this Helped!
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