die is thrown 4 times. If getting an odd number is a success, then the probability of getting exactly two successes is .... *
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Step-by-step explanation:
SOLUTION
Let X denote the number of odd numbers.
P(getting and odd number) = p =
36=12
∴ q = 1 – p =
1-12=12
Given, n = 4
∴ X ∼ B
(4,12)
The p.m.f. of X is given by
P(X = x) =
4Cx(12)x(12)4-x
=
4Cx(12)4,x = 0, 1,...,4
P(at most 2 successes)
= P(X ≤ 2)
= P(X = 0 or X = 1 or X = 2)
= P(X = 0 + P(X = 1) + P(X = 2)
=
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