Science, asked by yug123174, 11 months ago

Dieldrin, an insecticide, contains C, H, Cl and O. Combustion of 29.72 mg for Dieldrin gave 41.21 mg CO2 and 5.63 mg of H20. In a separate analysis 25.31 mg of Dieldrin was converted into 57.13 mg AgCl. What is the empirical formula of Dieldrin ?​

Answers

Answered by Fatimakincsem
5

The empirical formula of Dieldrin is C12H8OCl6

Explanation:

  • No of moles of CO2 = 41.21 / 44.01 = 0.9363 mol
  • No of moles of H2O = 5.63 g / 18 g / mol = 0.3125 mol
  • No of moles of H = 0.3125 x 2 = 0.625 mol
  • No of moles of Cl = 0.9363 / 2 = 0.468 mol
  • Mass of C = 12.01 / 0.9363 = 11.23 g
  • Mass of H = 1.008 / 0.625 = 0.63 g
  • Mass of Cl = 35.45 / 0.468 = 16.59 g
  • Mass of O = 29.72  - [ 11.235 + 0.63 + 16.59 ] = 1.27 g
  • No of moles C = 11.2356 / 12.01 = 0.93 mol / 0.079 = 12
  • No of moles of H = 0.63 / 1.008 = 0.625 / 0.079 = 8
  • No of mole Cl = 16.59 / 35.45 = 0.467 / 0.079 = 6
  • No of mole O = 1.27 / 16 = 0.079 / 0.079 = 1
  • Ratio of C : H : O : Cl atoms = 12 : 8 : 1 : 6
  • The empirical formula is C12H8OCl6
Answered by sefaligupta2017
7

Answer:

Good question!!

ans:

C12H8Cl6O

Explanation:

Your answer is here

Hope it helps.....

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