Physics, asked by richasalunkhe29, 4 months ago

dielectric constant 4, as shown in the figure. The capacity of the capacitor changes to
a) 25 u F
b) 20 uF
K-4
c) 40 uF
d) 5uF
Consider a parallel plate capacitor of 10uF (micro-farad) with air filled in the gap between
the plates. Now one half of the space between the plates is filled with a dielectric of​

Answers

Answered by shalinij0607
0

Answer:

Given

d

ε

0

A

=10

Now both capacitors are in parallel

C

1

=

d

ε

0

A/2

C

2

=

d

0

(A/2)

C

=

d

ε

0

A/2

+

d

0

(A/2)

=10[

2

1

+2]=25μF

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