Diesel cycle operates at a pressure of 1 bar at the beginning of Compression and volume is compressed to 1/16 th. Of the initial volume . Heat is supplied until the volume is twice that of clearance volume . Calculate the mean effective pressure of the cycle . γ= 1.4
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Given:
P1 = 1 bar
V1 = V
V2 = V/16
V3 = 2 V2
γ= 1.4
To Find :
The mean effective pressure of the cycle.
Solution:
P1V1^γ = P2V2^γ
we can find P2 from,
P2 = (16/1)^1.4
= 48.5 bar
P2,P3 = 48.5 bar
Similarly to find P4
P4 = P3 * (V3/V4)^1.4
= 48.5 * ((1/8)^1.4)
= 2.63 bar
Peff = Work done/ V1 - V2
= (P2*(V3/V2 - 1) + (P3(V3/V2) - P4(V4/V2))/ (γ-1) - (-P1(V1/V2) + P2)/γ-1)/V1 - V2
= 48.5*(2-1) +(48.5*-2.63*16)/0.4 - (-1*16+48.5)/0.4)/15
= 6.94 bar
Therefore, The mean effective pressure is 6.94 bar.
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