Question

Diethyl ether on heating with conc. HI gives two moles of(a) ethanol (b) iodoform(c) ethyl iodide (d) methyl iodide

Answer 1

Your answer is Ethyl iodide.

Answer 2

Answer:

(c) ethyl iodide is the correct answer.

Explanation:

Diethyl ether has formula (C2H5)2O.

Here, diethyl alcohol is reacted with concentrated HI that is hydrogen Iodide.

In this reaction, the C-O-C bond is broken.

Ethers are inert compunds.

The C-O-C bond is quite stable.

Ethers can be cleaved by strong acids.

HI is a strong acid.

Ethers can be cleaved by HI because it is sufficiently acidic to protonate ethers.

Note:

The order of reactivity of hydrogen halides is HI>HBr>HCl.

In this reaction, diethyl ethers when reacts with concentrated HI, it gives two molecules of alkyl halide.

The reaction is written as follows:

C2H5-O-C2H5 + 2HI ===> 2C2H5I + H2O.

Heat is required for this reaction.