diferentaition of y = 1/ root of 2x
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hii
y = 1 /√2x
dy/dx = d/dx ( 1 / √2)
now just use the formulae of quotient rule of differentiation.
the formulae goes like this :-
if y = u / v then,
dy / dx = {v [du / dx] - u [dv / dx] } / v^2
now in place of 'u' put 1 and in place of 'v' put √2 ...
u will get the answer....
hope it helps uhh!!!!☺☺
y = 1 /√2x
dy/dx = d/dx ( 1 / √2)
now just use the formulae of quotient rule of differentiation.
the formulae goes like this :-
if y = u / v then,
dy / dx = {v [du / dx] - u [dv / dx] } / v^2
now in place of 'u' put 1 and in place of 'v' put √2 ...
u will get the answer....
hope it helps uhh!!!!☺☺
mouryan:
thanks bro but i got the answer before u commented anyways thanks a lot for u r help
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