Question

diferentiation root 1+ tanx​

Answer 1

Answer:

Move (x−1)−12 ( x - 1 ) - 1 2 to the denominator using the negative exponent rule b−n=1bn b - n = 1 b n .

By the Sum Rule, the derivative of x−1 with respect to x is ddx[x]+ddx[−1] d d x [ x ] + d d x [ - 1 ] .

Differentiate using the Power Rule which states that ddx[xn] d d x [ x n ] is nxn−1 n x n - 1 where n=1 .

Step-by-step explanation:

Hope this could help you mark me as brainist and a thanks for ans please please