Diferrence between two no. is 16. If 1/3 of smaller no. is greater than 1/7 of the larger no. by 4 find the no.
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Answer:
greater number is 49 and Smaller number is 33.
Step-by-step explanation:
Let x = samller number
and y = greater number
According to the given question,
y-x = 16 (Equation 1)
x/3- y/7 = 4 (Equation 2)
Putting value of x = (y -16) from equation 1 , in equation 2.
(y -16)/3 -y/7 = 4
On taking LCM of 3 and 7 (=21)
(7y-112-3y)/21 = 4
4y -112 = 84
4y = 84 +112
4y = 196
y = 49
Putting the value of y in equation 1
y - x = 16
49 -x = 16
49 - 16 = x
x = 33
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