diff w.r.t.x y=(25)^log(sec x) - (16)^log (tan x)
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Step-by-step explanation:
Hey your quest was not clear enough foe me...But i have tried answering from what i understood....So if the answer is wrong pls tell me.
y= -
=> We know 25= 5^2 and 16 =4^2
Substitute,
=>y= -
We also know = n log x
Apply this
=>y= -
Now we know, log a to base a =1
=>y= sec^2x - tan^2x
=> y=1
=> dy/dx = 0
Hope it helps. Pls mark as brainliest
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