Physics, asked by SatvikVats3006, 9 months ago

Diffentiation of y=(5x -2)^3
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Answers

Answered by Anonymous
43

Given:

Function \bf\:y=\sf\:(5x-2){}^{3}

To Find :

\dfrac{dy}{dx}

Formulas :

1) \: \frac{d(x {}^{n} )}{dx}  = nx {}^{n - 1}

2) \frac{d(constant)}{dx}  = 0

3) \frac{d(sinx)}{dx}  = cosx

4) \frac{d(cosx)}{dx}  = -sinx

Solution :

y = (5x - 2) {}^{3}

Now Differentiate with respect to x

 \bf \frac{dy}{dx}  =  \frac{d(5x - 2) {}^{3} }{d(5x - 2)}   \times  \frac{d(5x - 2)}{dx}

 \sf  \frac{dy}{dx}  = 3(5x - 2) {}^{2}  \times 5

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More About Differention:

1) A function is said to be differentiable at a point, if there exists a unique tangent at that point .

2)Every polynomial function is differentiable at each x∈R .

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