Diffentiation proof of e^x
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Proof of e ^x : by ln(x)
Given : ln(x) = 1/x; Chain Rule; x = 1.
Solve:
(1) ln(e ^x ) = x = 1
ln(e ^x ) = ln(u) e ^x (Set u=e ^x )
= 1/u e ^x = 1/e ^x e ^x = 1 (equation 1)
e ^x = e ^x Q.E.D.
Given : ln(x) = 1/x; Chain Rule; x = 1.
Solve:
(1) ln(e ^x ) = x = 1
ln(e ^x ) = ln(u) e ^x (Set u=e ^x )
= 1/u e ^x = 1/e ^x e ^x = 1 (equation 1)
e ^x = e ^x Q.E.D.
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