difference and product is 32 and 2145. sum is?
Answers
Answered by
0
x-y=32
x=y+32
x*y=2145
y*(32+y)=2145
y^2+32y-2145=0
y=33,-65
x=65,-33
x=y+32
x*y=2145
y*(32+y)=2145
y^2+32y-2145=0
y=33,-65
x=65,-33
Answered by
2
(a+b)^2=a^2 + b^2+ 2ab eq (1)
(a-b)^2 = a^2 + b^2 - 2ab eq (2)
from eq (2), we get,
a^2 + b^2 = (a-b)^2 + 2ab eq (3)
put this value of a^2 + b^2 in eq (1)
we get,
(a+b)^2 = (a-b)^2 + 2ab + 2ab
= (a-b)^2 + 4ab
= 32^2 + 4 * 2145
= 9604
(a+b) = (9604)^1/2
= 98 ans.
hope it helps,thnak you
(a-b)^2 = a^2 + b^2 - 2ab eq (2)
from eq (2), we get,
a^2 + b^2 = (a-b)^2 + 2ab eq (3)
put this value of a^2 + b^2 in eq (1)
we get,
(a+b)^2 = (a-b)^2 + 2ab + 2ab
= (a-b)^2 + 4ab
= 32^2 + 4 * 2145
= 9604
(a+b) = (9604)^1/2
= 98 ans.
hope it helps,thnak you
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