Question

Difference between 2 numbers is 30. Twice
the greater number is less than 7 times the
smaller number by 5 . Find the numbers.​

Answer 1

Answer:

let x and y be two numbers

x-y = 30

then x = 30+y

according to problem,

2x = 7y-5

2(30+y) = 7y -5

60+2y = 7y-5

60+5 = 7y-2y

65 = 5y

y= 65/5

y= 13

therefore smallest number y is 13

and the largest number x is 30 + 13 = 43