Question

Difference between area and perimeter of a square is 96. Find the length of diagonal of the square?

Answer 1

Step-by-step explanation:

L×L-4L=96

$L^{2}$-4L-96=0

L^2-12L+8L-96=0

L(L-12)+8(L-12)=0

(L+8)(L-12)=0

L=12

Diagonal=$\sqrt{12^{2}+ 12^{2} }$

=12$\sqrt{2}$