Difference between biotechnological and non biotechnological products in marketing
Answers
Traditional medicine is a broad term used to define any non-Western medical practice. Ethno pharmacology is a diversified approach to drug discovery involving the description, observation and experimental investigation of indigenous drugs and their biologic activities. According to the World Health Organization (WHO), almost 65% of the world's population has incorporated into their primary modality of health care. There are numerous advantages and disadvantages of traditional medicine. Most traditional medicines are well tolerated by the patient while in some cases bio-pharmaceutical products are not.
Another advantage to traditional medicine is cost. Cost is much less than biopharmaceuticals. Yet another advantage of traditional medicines is their availability. They are available without a prescription, and some can simply be grown at home. While the high cost of biopharmaceuticals and the low reimbursement levels from insurance companies present a major challenge. It is needed to explore various strategies to counter this challenge such as developing technologies that bring down the cost of drugs as well as manufacturing biopharmaceuticals with substantial market size.
Explanation:
Given: d=3
We know:
an=a+(n−1)d
∴a20−a15=[a+19d]−[a+14d]
=5d
=5×3
=15
Hence, the answer is 15.
Given: d=3
We know:
an=a+(n−1)d
∴a20−a15=[a+19d]−[a+14d]
=5d
=5×3
=15
Hence, the answer is 15.
Given: d=3
We know:
an=a+(n−1)d
∴a20−a15=[a+19d]−[a+14d]
=5d
=5×3
=15
Hence, the answer is 15.
Given: d=3
We know:
an=a+(n−1)d
∴a20−a15=[a+19d]−[a+14d]
=5d
=5×3
=15
Hence, the answer is 15.
Given: d=3
We know:
an=a+(n−1)d
∴a20−a15=[a+19d]−[a+14d]
=5d
=5×3
=15
Hence, the answer is 15.
Given: d=3
We know:
an=a+(n−1)d
∴a20−a15=[a+19d]−[a+14d]
=5d
=5×3
=15
Hence, the answer is 15.
Given: d=3
We know:
an=a+(n−1)d
∴a20−a15=[a+19d]−[a+14d]
=5d
=5×3
=15
Hence, the answer is 15.
Given: d=3
We know:
an=a+(n−1)d
∴a20−a15=[a+19d]−[a+14d]
=5d
=5×3
=15
Hence, the answer is 15.
Given: d=3
We know:
an=a+(n−1)d
∴a20−a15=[a+19d]−[a+14d]
=5d
=5×3
=15
Hence, the answer is 15.
Given: d=3
We know:
an=a+(n−1)d
∴a20−a15=[a+19d]−[a+14d]
=5d
=5×3
=15
Hence, the answer is 15.
Given: d=3
We know:
an=a+(n−1)d
∴a20−a15=[a+19d]−[a+14d]
=5d
=5×3
=15
Hence, the answer is 15.
Given: d=3
We know:
an=a+(n−1)d
∴a20−a15=[a+19d]−[a+14d]
=5d
=5×3
=15
Hence, the answer is 15.