Question

Difference between energy of electron in third and second bohr orbit for He+is E then ionisation energy for Li+2 will be

Answer 1

Answer:

In hydrogen atom, the energy of the electron in the first and second Bohr orbit is 13.6 eV and 3.4 eV respectively.

The difference in the energy in the two orbits is 13.6eV−3.4eV=10.2eV.

Answer 2

Explanation:

ΔE = -2.41 × 10−12 -(-5.42 × 10−12)

= 3.01 × 10−12 erg

ΔE = hv ⇒ λ= vc = 3.01×10−12/(6.62×10−27)3×1010

= 6.6 × 10−5

= 6.6 × 10−5 × 108

= 6.6 × 103