Math, asked by devrouth3339, 5 months ago

difference between father and son age is 30 years, after 3 years father's age is 6 times than son's age, find their present age​

Answers

Answered by Anonymous
0

Answer:

Hee Buddy Ans is this Hope U liked it ..

Step-by-step explanation:

Let son’s age be x so father ‘s age is x+30. After 10 years x+30+10=3(x+10) or x=5 ie age of son and father is 35. After 10 years son will be 15 and father will be 45 which is 3 time son’s age that time.

Answered by ItzDinu
0

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F = father’s age

S = son’s age

F = 6*s

F = s + 35

i.e. 6 × s = s + 35

i.e. 5 × s = 35

Thus, S = 7.

The father is 42, the son is 7 years old.

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