difference between si and ci for 3 yrs at 10%p.a,when the interest is compounded annually on ₹30000
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s.i=(p*r*t)/100
=(30000*10*3)/100=9000
amount after3 years become= 39000
for c.i,
amount= p(1+r/100)^n
=30000(1+0.1)^3
=30000(1.1)^3=30000*1.331=39930
diffrence=39930-39000=930
=(30000*10*3)/100=9000
amount after3 years become= 39000
for c.i,
amount= p(1+r/100)^n
=30000(1+0.1)^3
=30000(1.1)^3=30000*1.331=39930
diffrence=39930-39000=930
cuterushika22ku:
ur ans is wrong
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