Difference between the length and breadth of a rectangle is 6m and its perimeter is 72m then its area is?
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Answered by
2
given,
perimeter=72m
let breadth be x
length =6+x
given, perimeter=72
=>2(l+b)=72
=>2(x+6+x)=72
=>2(2x+6)=72
=>2x+6=36
=>2x=30
=>x=30/2=15
breadth=15m
length=15+6=21m
area=length×bredth=15×21=315m²
HOPE U CAN UNDERSTAND
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perimeter=72m
let breadth be x
length =6+x
given, perimeter=72
=>2(l+b)=72
=>2(x+6+x)=72
=>2(2x+6)=72
=>2x+6=36
=>2x=30
=>x=30/2=15
breadth=15m
length=15+6=21m
area=length×bredth=15×21=315m²
HOPE U CAN UNDERSTAND
PLS MARK IT AS BRAINLIEST
nikki1231:
pls mark it as brainliest
Answered by
2
let l be length and breadth be b
so ATQ,
l-b=6
l=6+b---(1)
perimeter=72
2 (l+b)=72----(2)
(1) in (2)
2 (6+b+b)=72
2 (6+2b)=72
12+4b=72
b=72-12/4
b=15m---(3)
(3) in (1)
l=15+6
l=21m
area =l ×b
area= 15×21
area=315m^2
hope it helps!!! Cheers!!!
so ATQ,
l-b=6
l=6+b---(1)
perimeter=72
2 (l+b)=72----(2)
(1) in (2)
2 (6+b+b)=72
2 (6+2b)=72
12+4b=72
b=72-12/4
b=15m---(3)
(3) in (1)
l=15+6
l=21m
area =l ×b
area= 15×21
area=315m^2
hope it helps!!! Cheers!!!
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