difference between the place values of two sixes in 645162 is
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place value of 1st 6= 60
place value of 2nd 6= 600000
difference=600000-60=599940
place value of 2nd 6= 600000
difference=600000-60=599940
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Answer:
The difference between the place values of two sixes in
645162 is = 600000 - 60 = 599940.
Step-by-step explanation:
- Place value of a digit in a number is the value of that digit in the number. For example, the 6 in 360 represents 6 tens, or 60; however, the place value of 6 in 6,006 is 6 thousands, or 6,000.
- Place value describes the position of a digit in a number. Each digit of a number has a place in that number.
- When the number is represented in general form, the position of each digit will be expanded. Those positions start from a unit place. The order of place value of digits in a number from right to left is as follows: units, tens, hundreds, thousands, ten thousand, a hundred thousand, and so on.
- The given number is 645162.
- Consider the 6 in the tens place in the number 645162.
The place value of the underlined 6 is 6×10 = 60.
- Now, Consider another 6 in the number 645162.
The place value of the underlined 6 is 6×100000= 600000
Hence, the difference between the place values of two sixes in 645162 is = 600000 - 60 = 599940.
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