Math, asked by deepalisaini322, 1 year ago

difference between the place values of two sixes in 645162 is

Answers

Answered by SakshiSingh234
22
place value of 1st 6= 60
place value of 2nd 6= 600000
difference=600000-60=599940
Answered by ankhidassarma9
0

Answer:

The difference between the place values of two sixes in

645162 is = 600000 - 60 = 599940.

Step-by-step explanation:

  • Place value of a digit in a number  is the value of that digit in the number. For example, the 6 in 360 represents 6 tens, or 60; however, the place value of 6 in 6,006 is 6 thousands, or 6,000.
  • Place value  describes the position  of a digit in a number. Each digit  of a number has a place in that number.
  • When the number is represented in general form, the position of each digit will be expanded. Those positions start from a unit place. The order of place value of digits in a number from right to left is as follows: units, tens, hundreds, thousands, ten thousand, a hundred thousand, and so on.
  • The given number is 645162.
  • Consider the 6 in the tens place in the number 645162.

The place value of the underlined 6 is 6×10 = 60.

  • Now, Consider another 6 in the number 645162.

The place value of the underlined 6 is 6×100000= 600000

Hence, the difference between the place values of two sixes in 645162 is = 600000 - 60 = 599940.

To know more about Place Value, click here ->

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