Math, asked by datlasiva123, 17 days ago

difference between the points (5, 1 ) (5, 5)

Answers

Answered by s1271sreeja4825
0

Answer:

Answer:-

Given:

Distance between the points (5 , - 2) ; (1 , a) is 5 units.

We know that,

Distance between two points \sf{(x_1 , y_1)}(x

1

,y

1

) and \sf{(x_2 , y_2)}(x

2

,y

2

) = \sf \large{\sqrt{{(x_2 - x_1)}^{2} + {(y_2 - y_1)}^{2}}}

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

\begin{gathered} \sf \implies \: \sqrt{ {(1 - 5)}^{2} + {(a + 2)}^{2} } = 5 \\ \end{gathered}

(1−5)

2

+(a+2)

2

=5

On squaring both sides we get,

\begin{gathered} \sf \implies{( \sqrt{ {( - 4)}^{2} + {(a + 2)}^{2} } })^{2} = {5}^{2} \\ \\ \sf \implies \: 16 + {(a + 2)}^{2} = 25 \\ \\ \sf \implies \: {(a + 2)}^{2} = 25 - 16 \\ \\ \sf \implies \: {(a + 2)}^{2} = 9 \\ \\ \sf \implies \: a + 2 = \sqrt{9} \\ \\ \sf \implies \: a + 2 = \pm 3 \\ \\ \implies \sf \large{ a = 1 \: (or) \: - 5}\end{gathered}

⟹(

(−4)

2

+(a+2)

2

)

2

=5

2

⟹16+(a+2)

2

=25

⟹(a+2)

2

=25−16

⟹(a+2)

2

=9

⟹a+2=

9

⟹a+2=±3

⟹a=1(or)−5

Hence, the value of a is 1 or - 5.

Answered by Anonymous
1

Answer:

(0,-4)

Step-by-step explanation:

5-5 0

1-5 -4

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