Question

Difference between the square of two consecutive natural numbers are 99. find the number.​

Answer 1

Step-by-step explanation:

1. x
2. $x \: and \: x + 1 \: are \: two \: consecutive \: numbers \\ (x + 1) ^{2} - {x}^{2} = 99 \\ {x }^{2} + 2x + 1 - {x}^{2} = 99 \\2x + 1 = 99 \\ 2x = 99 - 1 \\ 2x = 98 \\ x = 98 \div 2 \\ x = 49 \\ x + 1 = 49 + 1 \\ x + 1 = 50$