Question

Difference between the square s of two consecutive number is 95.find the numbers

Answer 1

Answer:

- 48 and - 49

Step-by-step explanation:

Let the consecutive numbers be X and X+1

Given that

x^2 - (x+1)^2 = 95

(x+x+1)(x-x-1) =95

(2x+1)(-1)=95

2X = -96

X= -48

Hence the numbers are -48 and -49

Answer 2

$hi \: mate \\ hope \: this\: help \: you \\ let \: the \: first \: number \: be \: x \\ then \: second \: number \: will \: be \: x + 1 \\ according \: to \: question \\ ({x + 1})^{2} - {x }^{2} = 95 \\ {x}^{2} + 2x + 1 - {x}^{2} = 95 \\ 2x + 1 = 95 \\ 2x = 95 - 1 \\ 2x = 94 \\ x = 94 \div 2 \\ x = 47 \\ first \: number \: is \: 47 \\ and \: second \: number \: is \: 47 + 1 = 48$