Difference between two numbers is 30.Twice the greater number is less than 7 times the smaller number by 5. Find the numbers.
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Answer:
x = 41 and y = 11
Step-by-step explanation:
let the two no.s be x and y where x is the greater no. and y is the smaller no.
GIVEN : x - y = 30 ----- (1)
2x < 7y by 5
i.e. 2x = 7y + 5 ----- (2)
By solving equation (1) and (2)...we get
x = 41 and y = 11.
41 - 11 = 30
2(41) = 7 (11) + 5
82 = 77 +5 => 82.
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